Base | Representation |
---|---|
bin | 101111100101110100… |
… | …100110110101110111 |
3 | 11212220021102221220010 |
4 | 233211310212311313 |
5 | 1314123201211203 |
6 | 35250351111303 |
7 | 3456213226542 |
oct | 574564466567 |
9 | 155807387803 |
10 | 51100413303 |
11 | 1a74293a935 |
12 | 9aa1512533 |
13 | 4a84a36864 |
14 | 268a939859 |
15 | 14e12ad303 |
hex | be5d26d77 |
51100413303 has 16 divisors (see below), whose sum is σ = 71726144000. Its totient is φ = 32271125760.
The previous prime is 51100413289. The next prime is 51100413319. The reversal of 51100413303 is 30331400115.
It is not a de Polignac number, because 51100413303 - 218 = 51100151159 is a prime.
It is a super-2 number, since 2×511004133032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 51100413303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51100413383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 761298 + ... + 825696.
It is an arithmetic number, because the mean of its divisors is an integer number (4482884000).
Almost surely, 251100413303 is an apocalyptic number.
51100413303 is a deficient number, since it is larger than the sum of its proper divisors (20625730697).
51100413303 is a wasteful number, since it uses less digits than its factorization.
51100413303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78342.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 51100413303 its reverse (30331400115), we get a palindrome (81431813418).
The spelling of 51100413303 in words is "fifty-one billion, one hundred million, four hundred thirteen thousand, three hundred three".
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