Base | Representation |
---|---|
bin | 101111100101110111… |
… | …000011101001100111 |
3 | 11212220022122120221120 |
4 | 233211313003221213 |
5 | 1314123332234331 |
6 | 35250412545023 |
7 | 3456221543235 |
oct | 574567035147 |
9 | 155808576846 |
10 | 51101055591 |
11 | 1a743239453 |
12 | 9aa1782173 |
13 | 4a84c00001 |
14 | 268aa65955 |
15 | 14e1388796 |
hex | be5dc3a67 |
51101055591 has 8 divisors (see below), whose sum is σ = 68140662384. Its totient is φ = 34064409600.
The previous prime is 51101055589. The next prime is 51101055601. The reversal of 51101055591 is 19555010115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 51101055591 - 21 = 51101055589 is a prime.
It is a super-3 number, since 3×511010555913 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51101055581) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 699610 + ... + 769191.
It is an arithmetic number, because the mean of its divisors is an integer number (8517582798).
Almost surely, 251101055591 is an apocalyptic number.
51101055591 is a deficient number, since it is larger than the sum of its proper divisors (17039606793).
51101055591 is a wasteful number, since it uses less digits than its factorization.
51101055591 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1480401.
The product of its (nonzero) digits is 5625, while the sum is 33.
The spelling of 51101055591 in words is "fifty-one billion, one hundred one million, fifty-five thousand, five hundred ninety-one".
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