Base | Representation |
---|---|
bin | 100101001011100110001… |
… | …0000111011010101001111 |
3 | 200002112011122210120000211 |
4 | 1022113030100323111033 |
5 | 1132211033113314320 |
6 | 14511322313303251 |
7 | 1035124052462323 |
oct | 112271420732517 |
9 | 20075148716024 |
10 | 5110143104335 |
11 | 16a022161a015 |
12 | 6a6468704b27 |
13 | 2b0b66117499 |
14 | 13949197b983 |
15 | 8cdd718555a |
hex | 4a5cc43b54f |
5110143104335 has 4 divisors (see below), whose sum is σ = 6132171725208. Its totient is φ = 4088114483464.
The previous prime is 5110143104327. The next prime is 5110143104359. The reversal of 5110143104335 is 5334013410115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5110143104335 - 23 = 5110143104327 is a prime.
It is a super-2 number, since 2×51101431043352 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5110143104297 and 5110143104306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511014310429 + ... + 511014310438.
It is an arithmetic number, because the mean of its divisors is an integer number (1533042931302).
Almost surely, 25110143104335 is an apocalyptic number.
5110143104335 is a deficient number, since it is larger than the sum of its proper divisors (1022028620873).
5110143104335 is a wasteful number, since it uses less digits than its factorization.
5110143104335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1022028620872.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 5110143104335 in words is "five trillion, one hundred ten billion, one hundred forty-three million, one hundred four thousand, three hundred thirty-five".
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