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5110143104335 = 51022028620867
BaseRepresentation
bin100101001011100110001…
…0000111011010101001111
3200002112011122210120000211
41022113030100323111033
51132211033113314320
614511322313303251
71035124052462323
oct112271420732517
920075148716024
105110143104335
1116a022161a015
126a6468704b27
132b0b66117499
1413949197b983
158cdd718555a
hex4a5cc43b54f

5110143104335 has 4 divisors (see below), whose sum is σ = 6132171725208. Its totient is φ = 4088114483464.

The previous prime is 5110143104327. The next prime is 5110143104359. The reversal of 5110143104335 is 5334013410115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5110143104335 - 23 = 5110143104327 is a prime.

It is a super-2 number, since 2×51101431043352 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5110143104297 and 5110143104306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 511014310429 + ... + 511014310438.

It is an arithmetic number, because the mean of its divisors is an integer number (1533042931302).

Almost surely, 25110143104335 is an apocalyptic number.

5110143104335 is a deficient number, since it is larger than the sum of its proper divisors (1022028620873).

5110143104335 is a wasteful number, since it uses less digits than its factorization.

5110143104335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1022028620872.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 5110143104335 in words is "five trillion, one hundred ten billion, one hundred forty-three million, one hundred four thousand, three hundred thirty-five".

Divisors: 1 5 1022028620867 5110143104335