Base | Representation |
---|---|
bin | 100101001011100110001… |
… | …1000010000001111110101 |
3 | 200002112011210102010201001 |
4 | 1022113030120100033311 |
5 | 1132211034111300023 |
6 | 14511322422403301 |
7 | 1035124105012060 |
oct | 112271430201765 |
9 | 20075153363631 |
10 | 5110145025013 |
11 | 16a0222711056 |
12 | 6a6469290531 |
13 | 2b0b6663a792 |
14 | 139491d1b8d7 |
15 | 8cdd74146ad |
hex | 4a5cc6103f5 |
5110145025013 has 4 divisors (see below), whose sum is σ = 5840165742880. Its totient is φ = 4380124307148.
The previous prime is 5110145024989. The next prime is 5110145025053. The reversal of 5110145025013 is 3105205410115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5110145025013 - 25 = 5110145024981 is a prime.
It is a super-2 number, since 2×51101450250132 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110145025053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365010358923 + ... + 365010358936.
It is an arithmetic number, because the mean of its divisors is an integer number (1460041435720).
Almost surely, 25110145025013 is an apocalyptic number.
It is an amenable number.
5110145025013 is a deficient number, since it is larger than the sum of its proper divisors (730020717867).
5110145025013 is an equidigital number, since it uses as much as digits as its factorization.
5110145025013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 730020717866.
The product of its (nonzero) digits is 3000, while the sum is 28.
The spelling of 5110145025013 in words is "five trillion, one hundred ten billion, one hundred forty-five million, twenty-five thousand, thirteen".
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