Base | Representation |
---|---|
bin | 1001100001001011… |
… | …11111100100011101 |
3 | 111012010210202022201 |
4 | 10300211333210131 |
5 | 40431204431443 |
6 | 2203030011501 |
7 | 240431160400 |
oct | 46045774435 |
9 | 14163722281 |
10 | 5110233373 |
11 | 2192658a73 |
12 | ba74a6b91 |
13 | 63594623b |
14 | 366997d37 |
15 | 1ed97d34d |
hex | 13097f91d |
5110233373 has 12 divisors (see below), whose sum is σ = 5946696000. Its totient is φ = 4378624152.
The previous prime is 5110233367. The next prime is 5110233383. The reversal of 5110233373 is 3733320115.
5110233373 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5110233373 - 213 = 5110225181 is a prime.
It is a super-2 number, since 2×51102333732 = 52228970253045914258, which contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110233353) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 130878 + ... + 165376.
It is an arithmetic number, because the mean of its divisors is an integer number (495558000).
Almost surely, 25110233373 is an apocalyptic number.
It is an amenable number.
5110233373 is a deficient number, since it is larger than the sum of its proper divisors (836462627).
5110233373 is a wasteful number, since it uses less digits than its factorization.
5110233373 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37536 (or 37529 counting only the distinct ones).
The product of its (nonzero) digits is 5670, while the sum is 28.
The square root of 5110233373 is about 71485.8963222816. The cubic root of 5110233373 is about 1722.4511398668.
Adding to 5110233373 its reverse (3733320115), we get a palindrome (8843553488).
The spelling of 5110233373 in words is "five billion, one hundred ten million, two hundred thirty-three thousand, three hundred seventy-three".
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