Base | Representation |
---|---|
bin | 100101001011101011100… |
… | …0111110001110101101011 |
3 | 200002112122100112210111102 |
4 | 1022113113013301311223 |
5 | 1132211421231134111 |
6 | 14511352341352015 |
7 | 1035131423650346 |
oct | 112272707616553 |
9 | 20075570483442 |
10 | 5110325255531 |
11 | 16a03054209a1 |
12 | 6a64b970860b |
13 | 2b0b94a92562 |
14 | 1394abc3545d |
15 | 8cde816613b |
hex | 4a5d71f1d6b |
5110325255531 has 4 divisors (see below), whose sum is σ = 5110330003200. Its totient is φ = 5110320507864.
The previous prime is 5110325255509. The next prime is 5110325255533. The reversal of 5110325255531 is 1355525230115.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 5110325255531 - 26 = 5110325255467 is a prime.
It is a super-2 number, since 2×51103252555312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5110325255533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100310 + ... + 3198548.
It is an arithmetic number, because the mean of its divisors is an integer number (1277582500800).
Almost surely, 25110325255531 is an apocalyptic number.
5110325255531 is a deficient number, since it is larger than the sum of its proper divisors (4747669).
5110325255531 is a wasteful number, since it uses less digits than its factorization.
5110325255531 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4747668.
The product of its (nonzero) digits is 112500, while the sum is 38.
The spelling of 5110325255531 in words is "five trillion, one hundred ten billion, three hundred twenty-five million, two hundred fifty-five thousand, five hundred thirty-one".
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