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5110340035 = 519188928477
BaseRepresentation
bin1001100001001100…
…11001100111000011
3111012011000011122011
410300212121213003
540431221340120
62203032153351
7240432113353
oct46046314703
914164004564
105110340035
112192721119
12ba7538857
13635982958
143669c4b63
151ed99ec5a
hex1309999c3

5110340035 has 16 divisors (see below), whose sum is σ = 6458810400. Its totient is φ = 3870913536.

The previous prime is 5110340023. The next prime is 5110340057. The reversal of 5110340035 is 5300430115.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 5110340035 - 25 = 5110340003 is a prime.

It is a super-2 number, since 2×51103400352 = 52231150546647602450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5110339988 and 5110340015.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 165217 + ... + 193693.

It is an arithmetic number, because the mean of its divisors is an integer number (403675650).

Almost surely, 25110340035 is an apocalyptic number.

5110340035 is a deficient number, since it is larger than the sum of its proper divisors (1348470365).

5110340035 is a wasteful number, since it uses less digits than its factorization.

5110340035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30390.

The product of its (nonzero) digits is 900, while the sum is 22.

The square root of 5110340035 is about 71486.6423536593. The cubic root of 5110340035 is about 1722.4631235860.

The spelling of 5110340035 in words is "five billion, one hundred ten million, three hundred forty thousand, thirty-five".

Divisors: 1 5 19 95 1889 9445 28477 35891 142385 179455 541063 2705315 53793053 268965265 1022068007 5110340035