Base | Representation |
---|---|
bin | 101111100110000010… |
… | …101011110001001111 |
3 | 11212220112101102220012 |
4 | 233212002223301033 |
5 | 1314130122303003 |
6 | 35251002143435 |
7 | 3456256466255 |
oct | 574602536117 |
9 | 155815342805 |
10 | 51104103503 |
11 | 1a744a30392 |
12 | 9aa27b1b7b |
13 | 4a857293cb |
14 | 268b21a5d5 |
15 | 14e178b8d8 |
hex | be60abc4f |
51104103503 has 4 divisors (see below), whose sum is σ = 51197530200. Its totient is φ = 51010676808.
The previous prime is 51104103499. The next prime is 51104103527. The reversal of 51104103503 is 30530140115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 51104103503 - 22 = 51104103499 is a prime.
It is a super-2 number, since 2×511041035032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51104103703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46712528 + ... + 46713621.
It is an arithmetic number, because the mean of its divisors is an integer number (12799382550).
Almost surely, 251104103503 is an apocalyptic number.
51104103503 is a deficient number, since it is larger than the sum of its proper divisors (93426697).
51104103503 is an equidigital number, since it uses as much as digits as its factorization.
51104103503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93426696.
The product of its (nonzero) digits is 900, while the sum is 23.
Adding to 51104103503 its reverse (30530140115), we get a palindrome (81634243618).
The spelling of 51104103503 in words is "fifty-one billion, one hundred four million, one hundred three thousand, five hundred three".
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