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51104555133 = 318439923849
BaseRepresentation
bin101111100110000100…
…011010000001111101
311212220120020101102020
4233212010122001331
51314130231231013
635251015550353
73456263360052
oct574604320175
9155816211366
1051104555133
111a745209735
129aa298b3b9
134a85856b48
14268b2d7029
1514e182a623
hexbe611a07d

51104555133 has 8 divisors (see below), whose sum is σ = 68143176000. Its totient is φ = 34067818848.

The previous prime is 51104555069. The next prime is 51104555153. The reversal of 51104555133 is 33155540115.

51104555133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 51104555133 - 26 = 51104555069 is a prime.

It is a super-2 number, since 2×511045551332 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51104555094 and 51104555103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51104555153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 406608 + ... + 517241.

It is an arithmetic number, because the mean of its divisors is an integer number (8517897000).

Almost surely, 251104555133 is an apocalyptic number.

It is an amenable number.

51104555133 is a deficient number, since it is larger than the sum of its proper divisors (17038620867).

51104555133 is a wasteful number, since it uses less digits than its factorization.

51104555133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 942291.

The product of its (nonzero) digits is 22500, while the sum is 33.

The spelling of 51104555133 in words is "fifty-one billion, one hundred four million, five hundred fifty-five thousand, one hundred thirty-three".

Divisors: 1 3 18439 55317 923849 2771547 17034851711 51104555133