Base | Representation |
---|---|
bin | 100101001011110000110… |
… | …1010110101001001001111 |
3 | 200002120002200112022222220 |
4 | 1022113201222311021033 |
5 | 1132212302031410041 |
6 | 14511422102310423 |
7 | 1035136003050024 |
oct | 112274152651117 |
9 | 20076080468886 |
10 | 5110502216271 |
11 | 16a03962a8141 |
12 | 6a6548a28413 |
13 | 2b0bc2640c5a |
14 | 1394c753b54b |
15 | 8ce0896dd66 |
hex | 4a5e1ab524f |
5110502216271 has 8 divisors (see below), whose sum is σ = 6833639852544. Its totient is φ = 3397183028760.
The previous prime is 5110502216263. The next prime is 5110502216273. The reversal of 5110502216271 is 1726122050115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 5110502216271 - 23 = 5110502216263 is a prime.
It is a super-2 number, since 2×51105022162712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110502216273) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2454610975 + ... + 2454613056.
It is an arithmetic number, because the mean of its divisors is an integer number (854204981568).
Almost surely, 25110502216271 is an apocalyptic number.
5110502216271 is a deficient number, since it is larger than the sum of its proper divisors (1723137636273).
5110502216271 is a wasteful number, since it uses less digits than its factorization.
5110502216271 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4909224381.
The product of its (nonzero) digits is 8400, while the sum is 33.
Adding to 5110502216271 its reverse (1726122050115), we get a palindrome (6836624266386).
The spelling of 5110502216271 in words is "five trillion, one hundred ten billion, five hundred two million, two hundred sixteen thousand, two hundred seventy-one".
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