Base | Representation |
---|---|
bin | 100101001011110001001… |
… | …0110000000000011100001 |
3 | 200002120010110211021211200 |
4 | 1022113202112000003201 |
5 | 1132212312431030103 |
6 | 14511423145031413 |
7 | 1035136201202610 |
oct | 112274226000341 |
9 | 20076113737750 |
10 | 5110513533153 |
11 | 16a03a1727736 |
12 | 6a6550785569 |
13 | 2b0bc4aa4032 |
14 | 1394c8c45877 |
15 | 8ce099570a3 |
hex | 4a5e25800e1 |
5110513533153 has 48 divisors (see below), whose sum is σ = 8709151027200. Its totient is φ = 2825893876320.
The previous prime is 5110513533149. The next prime is 5110513533161. The reversal of 5110513533153 is 3513353150115.
5110513533153 is a `hidden beast` number, since 5 + 1 + 10 + 513 + 53 + 31 + 53 = 666.
It is not a de Polignac number, because 5110513533153 - 22 = 5110513533149 is a prime.
It is a super-2 number, since 2×51105135331532 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5110513533113) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 30655138 + ... + 30821396.
It is an arithmetic number, because the mean of its divisors is an integer number (181440646400).
Almost surely, 25110513533153 is an apocalyptic number.
It is an amenable number.
5110513533153 is a deficient number, since it is larger than the sum of its proper divisors (3598637494047).
5110513533153 is a wasteful number, since it uses less digits than its factorization.
5110513533153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182042 (or 182039 counting only the distinct ones).
The product of its (nonzero) digits is 50625, while the sum is 36.
Adding to 5110513533153 its reverse (3513353150115), we get a palindrome (8623866683268).
The spelling of 5110513533153 in words is "five trillion, one hundred ten billion, five hundred thirteen million, five hundred thirty-three thousand, one hundred fifty-three".
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