Base | Representation |
---|---|
bin | 1001100001001110… |
… | …01000010011100101 |
3 | 111012011100220000002 |
4 | 10300213020103211 |
5 | 40431244000201 |
6 | 2203040231045 |
7 | 240433541111 |
oct | 46047102345 |
9 | 14164326002 |
10 | 5110531301 |
11 | 2192841897 |
12 | ba760b485 |
13 | 635a1ba25 |
14 | 366a34741 |
15 | 1ed9db76b |
hex | 1309c84e5 |
5110531301 has 4 divisors (see below), whose sum is σ = 5110713504. Its totient is φ = 5110349100.
The previous prime is 5110531297. The next prime is 5110531303. The reversal of 5110531301 is 1031350115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5110531301 - 22 = 5110531297 is a prime.
It is a super-2 number, since 2×51105313012 = 52235060357001505202, which contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5110531303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39155 + ... + 108416.
It is an arithmetic number, because the mean of its divisors is an integer number (1277678376).
Almost surely, 25110531301 is an apocalyptic number.
It is an amenable number.
5110531301 is a deficient number, since it is larger than the sum of its proper divisors (182203).
5110531301 is a wasteful number, since it uses less digits than its factorization.
5110531301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 182202.
The product of its (nonzero) digits is 225, while the sum is 20.
The square root of 5110531301 is about 71487.9801155411. The cubic root of 5110531301 is about 1722.4846123402.
Adding to 5110531301 its reverse (1031350115), we get a palindrome (6141881416).
The spelling of 5110531301 in words is "five billion, one hundred ten million, five hundred thirty-one thousand, three hundred one".
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