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5111034737 = 8447605071
BaseRepresentation
bin1001100001010010…
…00011001101110001
3111012012022110120212
410300221003031301
540431411102422
62203055113505
7240441035624
oct46051031561
914165273525
105111034737
112193056056
12ba7812895
13635b66c13
14366b25dbb
151eda8a9e2
hex130a43371

5111034737 has 4 divisors (see below), whose sum is σ = 5111648256. Its totient is φ = 5110421220.

The previous prime is 5111034679. The next prime is 5111034757. The reversal of 5111034737 is 7374301115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5111034737 is a prime.

It is a super-2 number, since 2×51110347372 = 52245352165641318338, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5111034757) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 294089 + ... + 310982.

It is an arithmetic number, because the mean of its divisors is an integer number (1277912064).

Almost surely, 25111034737 is an apocalyptic number.

It is an amenable number.

5111034737 is a deficient number, since it is larger than the sum of its proper divisors (613519).

5111034737 is an equidigital number, since it uses as much as digits as its factorization.

5111034737 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 613518.

The product of its (nonzero) digits is 8820, while the sum is 32.

The square root of 5111034737 is about 71491.5011522349. The cubic root of 5111034737 is about 1722.5411708621.

The spelling of 5111034737 in words is "five billion, one hundred eleven million, thirty-four thousand, seven hundred thirty-seven".

Divisors: 1 8447 605071 5111034737