5111041431 has 4 divisors (see below), whose sum is σ = 6814721912. Its totient is φ = 3407360952.

The previous prime is 5111041421. The next prime is 5111041457. The reversal of 5111041431 is 1341401115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5111041431 - 2⁵ = 5111041399 is a prime.

It is a super-2 number, since 2×5111041431² = 52245489018797055522, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5111041398 and 5111041407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111041421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 851840236 + ... + 851840241.

It is an arithmetic number, because the mean of its divisors is an integer number (1703680478).

Almost surely, 2^5111041431 is an apocalyptic number.

5111041431 is a deficient number, since it is larger than the sum of its proper divisors (1703680481).

5111041431 is a wasteful number, since it uses less digits than its factorization.

5111041431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1703680480.

The product of its (nonzero) digits is 240, while the sum is 21.

The square root of 5111041431 is about 71491.5479689732. The cubic root of 5111041431 is about 1722.5419228746.

Adding to 5111041431 its reverse (1341401115), we get a palindrome (6452442546).

The spelling of 5111041431 in words is "five billion, one hundred eleven million, forty-one thousand, four hundred thirty-one".