Base | Representation |
---|---|
bin | 100101001100000110000… |
… | …0000100001001000010111 |
3 | 200002121221012010202012010 |
4 | 1022120030000201020113 |
5 | 1132220230402411120 |
6 | 14512020355155303 |
7 | 1035162416535636 |
oct | 112301400411027 |
9 | 20077835122163 |
10 | 5111212544535 |
11 | 16a0720261299 |
12 | 6a67068a5b33 |
13 | 2b0ca6858436 |
14 | 139553a0351d |
15 | 8ce4aed17e0 |
hex | 4a60c021217 |
5111212544535 has 8 divisors (see below), whose sum is σ = 8177940071280. Its totient is φ = 2725980023744.
The previous prime is 5111212544521. The next prime is 5111212544569. The reversal of 5111212544535 is 5354452121115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5111212544535 - 24 = 5111212544519 is a prime.
It is a super-2 number, since 2×51112125445352 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111212544493 and 5111212544502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170373751470 + ... + 170373751499.
It is an arithmetic number, because the mean of its divisors is an integer number (1022242508910).
Almost surely, 25111212544535 is an apocalyptic number.
5111212544535 is a deficient number, since it is larger than the sum of its proper divisors (3066727526745).
5111212544535 is a wasteful number, since it uses less digits than its factorization.
5111212544535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 340747502977.
The product of its digits is 120000, while the sum is 39.
The spelling of 5111212544535 in words is "five trillion, one hundred eleven billion, two hundred twelve million, five hundred forty-four thousand, five hundred thirty-five".
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