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5111212544535 = 35340747502969
BaseRepresentation
bin100101001100000110000…
…0000100001001000010111
3200002121221012010202012010
41022120030000201020113
51132220230402411120
614512020355155303
71035162416535636
oct112301400411027
920077835122163
105111212544535
1116a0720261299
126a67068a5b33
132b0ca6858436
14139553a0351d
158ce4aed17e0
hex4a60c021217

5111212544535 has 8 divisors (see below), whose sum is σ = 8177940071280. Its totient is φ = 2725980023744.

The previous prime is 5111212544521. The next prime is 5111212544569. The reversal of 5111212544535 is 5354452121115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5111212544535 - 24 = 5111212544519 is a prime.

It is a super-2 number, since 2×51112125445352 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5111212544493 and 5111212544502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 170373751470 + ... + 170373751499.

It is an arithmetic number, because the mean of its divisors is an integer number (1022242508910).

Almost surely, 25111212544535 is an apocalyptic number.

5111212544535 is a deficient number, since it is larger than the sum of its proper divisors (3066727526745).

5111212544535 is a wasteful number, since it uses less digits than its factorization.

5111212544535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340747502977.

The product of its digits is 120000, while the sum is 39.

The spelling of 5111212544535 in words is "five trillion, one hundred eleven billion, two hundred twelve million, five hundred forty-four thousand, five hundred thirty-five".

Divisors: 1 3 5 15 340747502969 1022242508907 1703737514845 5111212544535