Base | Representation |
---|---|
bin | 10111001111100100011001… |
… | …01111011010000001100011 |
3 | 20200222022020001121022210212 |
4 | 23213302030233122001203 |
5 | 23144411320321410003 |
6 | 300412425010244335 |
7 | 13523516464050464 |
oct | 1347621457320143 |
9 | 220868201538725 |
10 | 51112472060003 |
11 | 1531674aa84392 |
12 | 5895b335866ab |
13 | 2269b683b46c3 |
14 | c89bdd290d6b |
15 | 5d984552add8 |
hex | 2e7c8cbda063 |
51112472060003 has 32 divisors (see below), whose sum is σ = 51805661847552. Its totient is φ = 50425560057600.
The previous prime is 51112472059997. The next prime is 51112472060029. The reversal of 51112472060003 is 30006027421115.
It is a cyclic number.
It is not a de Polignac number, because 51112472060003 - 26 = 51112472059939 is a prime.
It is a super-2 number, since 2×511124720600032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51112472060063) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24775797350 + ... + 24775799412.
It is an arithmetic number, because the mean of its divisors is an integer number (1618926932736).
Almost surely, 251112472060003 is an apocalyptic number.
51112472060003 is a deficient number, since it is larger than the sum of its proper divisors (693189787549).
51112472060003 is a wasteful number, since it uses less digits than its factorization.
51112472060003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4235.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 51112472060003 its reverse (30006027421115), we get a palindrome (81118499481118).
The spelling of 51112472060003 in words is "fifty-one trillion, one hundred twelve billion, four hundred seventy-two million, sixty thousand, three".
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