Base | Representation |
---|---|
bin | 1001100001010100… |
… | …01010011011100101 |
3 | 111012012212021201120 |
4 | 10300222022123211 |
5 | 40431444421222 |
6 | 2203105244153 |
7 | 240443362230 |
oct | 46052123345 |
9 | 14165767646 |
10 | 5111326437 |
11 | 2193235228 |
12 | ba7933659 |
13 | 635c39919 |
14 | 366ba0417 |
15 | 1edae715c |
hex | 130a8a6e5 |
5111326437 has 16 divisors (see below), whose sum is σ = 8246846592. Its totient is φ = 2748948480.
The previous prime is 5111326433. The next prime is 5111326447. The reversal of 5111326437 is 7346231115.
It is not a de Polignac number, because 5111326437 - 22 = 5111326433 is a prime.
It is a super-2 number, since 2×51113264372 = 52251315891150229938, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5111326398 and 5111326407.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5111326433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7158364 + ... + 7159077.
It is an arithmetic number, because the mean of its divisors is an integer number (515427912).
Almost surely, 25111326437 is an apocalyptic number.
It is an amenable number.
5111326437 is a deficient number, since it is larger than the sum of its proper divisors (3135520155).
5111326437 is a wasteful number, since it uses less digits than its factorization.
5111326437 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14317468.
The product of its digits is 15120, while the sum is 33.
The square root of 5111326437 is about 71493.5412257639. The cubic root of 5111326437 is about 1722.5739402019.
The spelling of 5111326437 in words is "five billion, one hundred eleven million, three hundred twenty-six thousand, four hundred thirty-seven".
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