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5111332041055 = 51953803495169
BaseRepresentation
bin100101001100001001100…
…1000010111000101011111
3200002122020111222210121011
41022120103020113011133
51132221002000303210
614512040304320051
71035165400332202
oct112302310270537
920078214883534
105111332041055
1116a0781759849
126a673a913027
132b0cc5537136
1413956582b939
158ce56737d8a
hex4a61321715f

5111332041055 has 8 divisors (see below), whose sum is σ = 6456419420400. Its totient is φ = 3873851652096.

The previous prime is 5111332041019. The next prime is 5111332041059. The reversal of 5111332041055 is 5501402331115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 5111332041055 - 211 = 5111332039007 is a prime.

It is a super-2 number, since 2×51113320410552 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111332041059) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26901747490 + ... + 26901747679.

It is an arithmetic number, because the mean of its divisors is an integer number (807052427550).

Almost surely, 25111332041055 is an apocalyptic number.

5111332041055 is a deficient number, since it is larger than the sum of its proper divisors (1345087379345).

5111332041055 is a wasteful number, since it uses less digits than its factorization.

5111332041055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53803495193.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 5111332041055 in words is "five trillion, one hundred eleven billion, three hundred thirty-two million, forty-one thousand, fifty-five".

Divisors: 1 5 19 95 53803495169 269017475845 1022266408211 5111332041055