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5111343503 = 73767294551
BaseRepresentation
bin1001100001010100…
…01110100110001111
3111012012220011010122
410300222032212033
540432000443003
62203105455155
7240443463050
oct46052164617
914165804118
105111343503
112193247032
12ba79414bb
13635c44616
14366ba6727
151edaec238
hex130a8e98f

5111343503 has 16 divisors (see below), whose sum is σ = 6088978944. Its totient is φ = 4199104800.

The previous prime is 5111343469. The next prime is 5111343541. The reversal of 5111343503 is 3053431115.

It is a cyclic number.

It is not a de Polignac number, because 5111343503 - 214 = 5111327119 is a prime.

It is a super-2 number, since 2×51113435032 = 52251664811320622018, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111343553) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 129923 + ... + 164628.

It is an arithmetic number, because the mean of its divisors is an integer number (380561184).

Almost surely, 25111343503 is an apocalyptic number.

5111343503 is a deficient number, since it is larger than the sum of its proper divisors (977635441).

5111343503 is a wasteful number, since it uses less digits than its factorization.

5111343503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 294662.

The product of its (nonzero) digits is 2700, while the sum is 26.

The square root of 5111343503 is about 71493.6605791031. The cubic root of 5111343503 is about 1722.5758573437.

Adding to 5111343503 its reverse (3053431115), we get a palindrome (8164774618).

The spelling of 5111343503 in words is "five billion, one hundred eleven million, three hundred forty-three thousand, five hundred three".

Divisors: 1 7 37 67 259 469 2479 17353 294551 2061857 10898387 19734917 76288709 138144419 730191929 5111343503