Base | Representation |
---|---|
bin | 101111100110101000… |
… | …110101101011001111 |
3 | 11212221020012121010102 |
4 | 233212220311223033 |
5 | 1314140202334201 |
6 | 35252000401315 |
7 | 3456440504615 |
oct | 574650655317 |
9 | 155836177112 |
10 | 51114105551 |
11 | 1a74a642043 |
12 | 9aa601623b |
13 | 4a8781bb92 |
14 | 268c6a16b5 |
15 | 14e25b526b |
hex | be6a35acf |
51114105551 has 4 divisors (see below), whose sum is σ = 51729938232. Its totient is φ = 50498272872.
The previous prime is 51114105487. The next prime is 51114105569. The reversal of 51114105551 is 15550141115.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15550141115 = 5 ⋅3110028223.
It is a cyclic number.
It is not a de Polignac number, because 51114105551 - 26 = 51114105487 is a prime.
It is a super-2 number, since 2×511141055512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51119105551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307916216 + ... + 307916381.
It is an arithmetic number, because the mean of its divisors is an integer number (12932484558).
Almost surely, 251114105551 is an apocalyptic number.
51114105551 is a deficient number, since it is larger than the sum of its proper divisors (615832681).
51114105551 is an equidigital number, since it uses as much as digits as its factorization.
51114105551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 615832680.
The product of its (nonzero) digits is 2500, while the sum is 29.
Adding to 51114105551 its reverse (15550141115), we get a palindrome (66664246666).
The spelling of 51114105551 in words is "fifty-one billion, one hundred fourteen million, one hundred five thousand, five hundred fifty-one".
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