5111443134301 has 4 divisors (see below), whose sum is σ = 5841649296352. Its totient is φ = 4381236972252.

The previous prime is 5111443134293. The next prime is 5111443134313. The reversal of 5111443134301 is 1034313441115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5111443134301 - 2³ = 5111443134293 is a prime.

It is a super-2 number, since 2×5111443134301² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111443134361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365103081015 + ... + 365103081028.

It is an arithmetic number, because the mean of its divisors is an integer number (1460412324088).

Almost surely, 2^{5111443134301} is an apocalyptic number.

It is an amenable number.

5111443134301 is a deficient number, since it is larger than the sum of its proper divisors (730206162051).

5111443134301 is an equidigital number, since it uses as much as digits as its factorization.

5111443134301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 730206162050.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 5111443134301 its reverse (1034313441115), we get a palindrome (6145756575416).

The spelling of 5111443134301 in words is "five trillion, one hundred eleven billion, four hundred forty-three million, one hundred thirty-four thousand, three hundred one".