5111614311131 has 4 divisors (see below), whose sum is σ = 5111637930432. Its totient is φ = 5111590691832.

The previous prime is 5111614311121. The next prime is 5111614311149. The reversal of 5111614311131 is 1311134161115.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5111614311131 - 2¹⁴ = 5111614294747 is a prime.

It is a super-2 number, since 2×5111614311131² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5111614311094 and 5111614311103.

It is not an unprimeable number, because it can be changed into a prime (5111614311121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11481995 + ... + 11918868.

It is an arithmetic number, because the mean of its divisors is an integer number (1277909482608).

Almost surely, 2^{5111614311131} is an apocalyptic number.

5111614311131 is a deficient number, since it is larger than the sum of its proper divisors (23619301).

5111614311131 is a wasteful number, since it uses less digits than its factorization.

5111614311131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23619300.

The product of its digits is 1080, while the sum is 29.

Adding to 5111614311131 its reverse (1311134161115), we get a palindrome (6422748472246).

The spelling of 5111614311131 in words is "five trillion, one hundred eleven billion, six hundred fourteen million, three hundred eleven thousand, one hundred thirty-one".