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5111656610551 = 34367148737353
BaseRepresentation
bin100101001100010011001…
…1110011111101011110111
3200002200002010201122020121
41022120212132133223313
51132222133043014201
614512132421112411
71035206421202021
oct112304636375367
920080063648217
105111656610551
1116a09289946a7
126a680b558707
132b10478581aa
14139596999011
158ce74e9b9a1
hex4a62679faf7

5111656610551 has 4 divisors (see below), whose sum is σ = 5111805382272. Its totient is φ = 5111507838832.

The previous prime is 5111656610477. The next prime is 5111656610581. The reversal of 5111656610551 is 1550166561115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5111656610551 - 219 = 5111656086263 is a prime.

It is a super-2 number, since 2×51116566105512 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5111656610498 and 5111656610507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111656610581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74334310 + ... + 74403043.

It is an arithmetic number, because the mean of its divisors is an integer number (1277951345568).

Almost surely, 25111656610551 is an apocalyptic number.

5111656610551 is a deficient number, since it is larger than the sum of its proper divisors (148771721).

5111656610551 is a wasteful number, since it uses less digits than its factorization.

5111656610551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148771720.

The product of its (nonzero) digits is 135000, while the sum is 43.

The spelling of 5111656610551 in words is "five trillion, one hundred eleven billion, six hundred fifty-six million, six hundred ten thousand, five hundred fifty-one".

Divisors: 1 34367 148737353 5111656610551