Search a number
-
+
5111756773741 = 39551129244691
BaseRepresentation
bin100101001100010110001…
…1100100101100101101101
3200002200100010012110022101
41022120230130211211231
51132222334213224431
614512150400015101
71035212045444002
oct112305434454555
920080303173271
105111756773741
1116a097a4877a2
126a6839001491
132b1062528057
141395a5dcd8a9
158ce7db84961
hex4a62c72596d

5111756773741 has 4 divisors (see below), whose sum is σ = 5111886057984. Its totient is φ = 5111627489500.

The previous prime is 5111756773733. The next prime is 5111756773847. The reversal of 5111756773741 is 1473776571115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5111756773741 - 23 = 5111756773733 is a prime.

It is a super-2 number, since 2×51117567737412 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5111706773741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64582795 + ... + 64661896.

It is an arithmetic number, because the mean of its divisors is an integer number (1277971514496).

Almost surely, 25111756773741 is an apocalyptic number.

It is an amenable number.

5111756773741 is a deficient number, since it is larger than the sum of its proper divisors (129284243).

5111756773741 is a wasteful number, since it uses less digits than its factorization.

5111756773741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 129284242.

The product of its digits is 4321800, while the sum is 55.

The spelling of 5111756773741 in words is "five trillion, one hundred eleven billion, seven hundred fifty-six million, seven hundred seventy-three thousand, seven hundred forty-one".

Divisors: 1 39551 129244691 5111756773741