Base | Representation |
---|---|
bin | 100101001100010110001… |
… | …1100100101100101101101 |
3 | 200002200100010012110022101 |
4 | 1022120230130211211231 |
5 | 1132222334213224431 |
6 | 14512150400015101 |
7 | 1035212045444002 |
oct | 112305434454555 |
9 | 20080303173271 |
10 | 5111756773741 |
11 | 16a097a4877a2 |
12 | 6a6839001491 |
13 | 2b1062528057 |
14 | 1395a5dcd8a9 |
15 | 8ce7db84961 |
hex | 4a62c72596d |
5111756773741 has 4 divisors (see below), whose sum is σ = 5111886057984. Its totient is φ = 5111627489500.
The previous prime is 5111756773733. The next prime is 5111756773847. The reversal of 5111756773741 is 1473776571115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5111756773741 - 23 = 5111756773733 is a prime.
It is a super-2 number, since 2×51117567737412 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5111706773741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64582795 + ... + 64661896.
It is an arithmetic number, because the mean of its divisors is an integer number (1277971514496).
Almost surely, 25111756773741 is an apocalyptic number.
It is an amenable number.
5111756773741 is a deficient number, since it is larger than the sum of its proper divisors (129284243).
5111756773741 is a wasteful number, since it uses less digits than its factorization.
5111756773741 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 129284242.
The product of its digits is 4321800, while the sum is 55.
The spelling of 5111756773741 in words is "five trillion, one hundred eleven billion, seven hundred fifty-six million, seven hundred seventy-three thousand, seven hundred forty-one".
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