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5112031114 = 24363585839
BaseRepresentation
bin1001100001011001…
…10110011110001010
3111012021012002100201
410300230312132022
540432134443424
62203132322414
7240452355541
oct46054663612
914167162321
105112031114
112193676703
12ba801340a
136361255a8
14366d05158
151edbd5d44
hex130b3678a

5112031114 has 8 divisors (see below), whose sum is σ = 7669817280. Its totient is φ = 2555425356.

The previous prime is 5112031103. The next prime is 5112031117. The reversal of 5112031114 is 4111302115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×51120311142 = 52265724221008161992, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112031091 and 5112031100.

It is not an unprimeable number, because it can be changed into a prime (5112031117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 284194 + ... + 301645.

It is an arithmetic number, because the mean of its divisors is an integer number (958727160).

Almost surely, 25112031114 is an apocalyptic number.

5112031114 is a deficient number, since it is larger than the sum of its proper divisors (2557786166).

5112031114 is a wasteful number, since it uses less digits than its factorization.

5112031114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 590204.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 5112031114 is about 71498.4693122867. The cubic root of 5112031114 is about 1722.6530978969.

Adding to 5112031114 its reverse (4111302115), we get a palindrome (9223333229).

The spelling of 5112031114 in words is "five billion, one hundred twelve million, thirty-one thousand, one hundred fourteen".

Divisors: 1 2 4363 8726 585839 1171678 2556015557 5112031114