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5112038387217 = 31704012795739
BaseRepresentation
bin100101001100011110100…
…1110110110111000010001
3200002201001202002220101010
41022120331032312320101
51132223423311342332
614512234340001133
71035222035224356
oct112307516667021
920081052086333
105112038387217
1116a1004443103
126a68b73901a9
132b10a8988c48
141395d157862d
158ce987609cc
hex4a63d3b6e11

5112038387217 has 4 divisors (see below), whose sum is σ = 6816051182960. Its totient is φ = 3408025591476.

The previous prime is 5112038387213. The next prime is 5112038387231. The reversal of 5112038387217 is 7127838302115.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5112038387217 - 22 = 5112038387213 is a prime.

It is a super-2 number, since 2×51120383872172 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5112038387213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852006397867 + ... + 852006397872.

It is an arithmetic number, because the mean of its divisors is an integer number (1704012795740).

Almost surely, 25112038387217 is an apocalyptic number.

It is an amenable number.

5112038387217 is a deficient number, since it is larger than the sum of its proper divisors (1704012795743).

5112038387217 is a wasteful number, since it uses less digits than its factorization.

5112038387217 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1704012795742.

The product of its (nonzero) digits is 564480, while the sum is 48.

The spelling of 5112038387217 in words is "five trillion, one hundred twelve billion, thirty-eight million, three hundred eighty-seven thousand, two hundred seventeen".

Divisors: 1 3 1704012795739 5112038387217