Base | Representation |
---|---|
bin | 100101001100011111000… |
… | …1111111011011100110101 |
3 | 200002201002221012112200000 |
4 | 1022120332033323130311 |
5 | 1132223442143222201 |
6 | 14512240145341513 |
7 | 1035222333221400 |
oct | 112307617733465 |
9 | 20081087175600 |
10 | 5112055445301 |
11 | 16a10130340a2 |
12 | 6a6901037899 |
13 | 2b10ac37c29c |
14 | 1395d3938d37 |
15 | 8ce99eced86 |
hex | 4a63e3fb735 |
5112055445301 has 36 divisors (see below), whose sum is σ = 8907779174112. Its totient is φ = 2921174533368.
The previous prime is 5112055445281. The next prime is 5112055445323. The reversal of 5112055445301 is 1035445502115.
5112055445301 is a `hidden beast` number, since 5 + 1 + 1 + 205 + 5 + 445 + 3 + 0 + 1 = 666.
It is not a de Polignac number, because 5112055445301 - 27 = 5112055445173 is a prime.
It is a super-2 number, since 2×51120554453012 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5112055443301) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 214654065 + ... + 214677878.
It is an arithmetic number, because the mean of its divisors is an integer number (247438310392).
Almost surely, 25112055445301 is an apocalyptic number.
It is an amenable number.
5112055445301 is a deficient number, since it is larger than the sum of its proper divisors (3795723728811).
5112055445301 is an equidigital number, since it uses as much as digits as its factorization.
5112055445301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429331972 (or 429331953 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
The spelling of 5112055445301 in words is "five trillion, one hundred twelve billion, fifty-five million, four hundred forty-five thousand, three hundred one".
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