Base | Representation |
---|---|
bin | 1110111000001101010… |
… | …00010100001110000101 |
3 | 1210212112021012121100010 |
4 | 13130012220110032011 |
5 | 31333430324340401 |
6 | 1030503034340433 |
7 | 51635214123501 |
oct | 7340650241605 |
9 | 1725467177303 |
10 | 511212340101 |
11 | 187893047581 |
12 | 830abb8a719 |
13 | 39290060448 |
14 | 1aa583a9301 |
15 | d470167ed6 |
hex | 7706a14385 |
511212340101 has 16 divisors (see below), whose sum is σ = 698352117120. Its totient is φ = 332443034880.
The previous prime is 511212340099. The next prime is 511212340123. The reversal of 511212340101 is 101043212115.
It is not a de Polignac number, because 511212340101 - 21 = 511212340099 is a prime.
It is a super-2 number, since 2×5112123401012 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (511712340101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 455361 + ... + 1108953.
It is an arithmetic number, because the mean of its divisors is an integer number (43647007320).
Almost surely, 2511212340101 is an apocalyptic number.
It is an amenable number.
511212340101 is a deficient number, since it is larger than the sum of its proper divisors (187139777019).
511212340101 is a wasteful number, since it uses less digits than its factorization.
511212340101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 659996.
The product of its (nonzero) digits is 240, while the sum is 21.
Adding to 511212340101 its reverse (101043212115), we get a palindrome (612255552216).
The spelling of 511212340101 in words is "five hundred eleven billion, two hundred twelve million, three hundred forty thousand, one hundred one".
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