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5112133 = 13393241
BaseRepresentation
bin10011100000000101000101
3100121201112021
4103200011011
52302042013
6301323141
761311115
oct23400505
910551467
105112133
112981904
1218664b1
13109cb40
14971045
156aea8d
hex4e0145

5112133 has 4 divisors (see below), whose sum is σ = 5505388. Its totient is φ = 4718880.

The previous prime is 5112127. The next prime is 5112137. The reversal of 5112133 is 3312115.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1954404 + 3157729 = 1398^2 + 1777^2 .

It is a cyclic number.

It is not a de Polignac number, because 5112133 - 25 = 5112101 is a prime.

It is a super-2 number, since 2×51121332 = 52267807619378, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196608 + ... + 196633.

It is an arithmetic number, because the mean of its divisors is an integer number (1376347).

Almost surely, 25112133 is an apocalyptic number.

It is an amenable number.

5112133 is a deficient number, since it is larger than the sum of its proper divisors (393255).

5112133 is a wasteful number, since it uses less digits than its factorization.

5112133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 393254.

The product of its digits is 90, while the sum is 16.

The square root of 5112133 is about 2261.0026536915. The cubic root of 5112133 is about 172.2664542341.

Adding to 5112133 its reverse (3312115), we get a palindrome (8424248).

The spelling of 5112133 in words is "five million, one hundred twelve thousand, one hundred thirty-three".

Divisors: 1 13 393241 5112133