Base | Representation |
---|---|
bin | 100101001100100001101… |
… | …0111111100100101000011 |
3 | 200002201022221000011211100 |
4 | 1022121003113330211003 |
5 | 1132224131201330110 |
6 | 14512252500345443 |
7 | 1035224426134011 |
oct | 112310327744503 |
9 | 20081287004740 |
10 | 5112141433155 |
11 | 16a1057625039 |
12 | 6a69259a5283 |
13 | 2b10c4127c83 |
14 | 13960111d8b1 |
15 | 8cea2817bc0 |
hex | 4a6435fc943 |
5112141433155 has 24 divisors (see below), whose sum is σ = 8863934547312. Its totient is φ = 2725586385984.
The previous prime is 5112141433153. The next prime is 5112141433183. The reversal of 5112141433155 is 5513341412115.
5112141433155 is a `hidden beast` number, since 5 + 1 + 1 + 214 + 1 + 433 + 1 + 5 + 5 = 666.
It is not a de Polignac number, because 5112141433155 - 21 = 5112141433153 is a prime.
It is a super-2 number, since 2×51121414331552 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5112141433153) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 18382224 + ... + 18658253.
It is an arithmetic number, because the mean of its divisors is an integer number (369330606138).
Almost surely, 25112141433155 is an apocalyptic number.
5112141433155 is a deficient number, since it is larger than the sum of its proper divisors (3751793114157).
5112141433155 is a wasteful number, since it uses less digits than its factorization.
5112141433155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37043555 (or 37043552 counting only the distinct ones).
The product of its digits is 36000, while the sum is 36.
The spelling of 5112141433155 in words is "five trillion, one hundred twelve billion, one hundred forty-one million, four hundred thirty-three thousand, one hundred fifty-five".
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