Base | Representation |
---|---|
bin | 100101001100100001101… |
… | …1111010001001000001100 |
3 | 200002201100001121200102222 |
4 | 1022121003133101020030 |
5 | 1132224132144233312 |
6 | 14512253005434512 |
7 | 1035224451346202 |
oct | 112310337211014 |
9 | 20081301550388 |
10 | 5112143352332 |
11 | 16a1058715a35 |
12 | 6a692656ba38 |
13 | 2b10c464a693 |
14 | 13960149d072 |
15 | 8cea2a96672 |
hex | 4a6437d120c |
5112143352332 has 12 divisors (see below), whose sum is σ = 9029860688520. Its totient is φ = 2532183155616.
The previous prime is 5112143352317. The next prime is 5112143352353. The reversal of 5112143352332 is 2332533412115.
It is a super-2 number, since 2×51121433523322 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112143352292 and 5112143352301.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5972129657 + ... + 5972130512.
It is an arithmetic number, because the mean of its divisors is an integer number (752488390710).
Almost surely, 25112143352332 is an apocalyptic number.
It is an amenable number.
5112143352332 is a deficient number, since it is larger than the sum of its proper divisors (3917717336188).
5112143352332 is a wasteful number, since it uses less digits than its factorization.
5112143352332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11944260280 (or 11944260278 counting only the distinct ones).
The product of its digits is 64800, while the sum is 35.
Adding to 5112143352332 its reverse (2332533412115), we get a palindrome (7444676764447).
The spelling of 5112143352332 in words is "five trillion, one hundred twelve billion, one hundred forty-three million, three hundred fifty-two thousand, three hundred thirty-two".
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