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51122001351 = 31572691333
BaseRepresentation
bin101111100111000110…
…111101010111000111
311212221210001202010110
4233213012331113013
51314144213020401
635252441524103
73456564561501
oct574706752707
9155853052113
1051122001351
111a7540452a3
129aa87a3633
134a89354a55
14268d758d71
1514e31249d6
hexbe71bd5c7

51122001351 has 12 divisors (see below), whose sum is σ = 68599690152. Its totient is φ = 33864206688.

The previous prime is 51122001317. The next prime is 51122001361. The reversal of 51122001351 is 15310022115.

It is not a de Polignac number, because 51122001351 - 211 = 51121999303 is a prime.

It is a super-2 number, since 2×511220013512 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51122001361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 271720 + ... + 419613.

It is an arithmetic number, because the mean of its divisors is an integer number (5716640846).

Almost surely, 251122001351 is an apocalyptic number.

51122001351 is a deficient number, since it is larger than the sum of its proper divisors (17477688801).

51122001351 is an equidigital number, since it uses as much as digits as its factorization.

51122001351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 691650 (or 691493 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 21.

Adding to 51122001351 its reverse (15310022115), we get a palindrome (66432023466).

The spelling of 51122001351 in words is "fifty-one billion, one hundred twenty-two million, one thousand, three hundred fifty-one".

Divisors: 1 3 157 471 24649 73947 691333 2073999 108539281 325617843 17040667117 51122001351