Base | Representation |
---|---|
bin | 100101001100100100000… |
… | …0111100110100000111011 |
3 | 200002201112110210100102100 |
4 | 1022121020013212200323 |
5 | 1132224312041101210 |
6 | 14512304422434443 |
7 | 1035226413550035 |
oct | 112311007464073 |
9 | 20081473710370 |
10 | 5112221034555 |
11 | 16a1098553818 |
12 | 6a6948592a23 |
13 | 2b1107778aab |
14 | 13960b920c55 |
15 | 8cea97dd5c0 |
hex | 4a6481e683b |
5112221034555 has 24 divisors (see below), whose sum is σ = 9011372675760. Its totient is φ = 2680305716160.
The previous prime is 5112221034541. The next prime is 5112221034587. The reversal of 5112221034555 is 5554301222115.
5112221034555 is a `hidden beast` number, since 51 + 1 + 2 + 2 + 21 + 0 + 34 + 555 = 666.
It is not a de Polignac number, because 5112221034555 - 218 = 5112220772411 is a prime.
It is a super-2 number, since 2×51122210345552 (a number of 26 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 962750836 + ... + 962756145.
It is an arithmetic number, because the mean of its divisors is an integer number (375473861490).
Almost surely, 25112221034555 is an apocalyptic number.
5112221034555 is a deficient number, since it is larger than the sum of its proper divisors (3899151641205).
5112221034555 is a wasteful number, since it uses less digits than its factorization.
5112221034555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1925507051 (or 1925507048 counting only the distinct ones).
The product of its (nonzero) digits is 60000, while the sum is 36.
The spelling of 5112221034555 in words is "five trillion, one hundred twelve billion, two hundred twenty-one million, thirty-four thousand, five hundred fifty-five".
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