Base | Representation |
---|---|
bin | 101111100111001010… |
… | …110100111011001011 |
3 | 11212221211222021002202 |
4 | 233213022310323023 |
5 | 1314144442442441 |
6 | 35252515350415 |
7 | 3456606314021 |
oct | 574712647313 |
9 | 155854867082 |
10 | 51123015371 |
11 | 1a75467812a |
12 | 9aa8bb240b |
13 | 4a8961b46c |
14 | 268d940711 |
15 | 14e327519b |
hex | be72b4ecb |
51123015371 has 8 divisors (see below), whose sum is σ = 52890333600. Its totient is φ = 49355994240.
The previous prime is 51123015347. The next prime is 51123015389. The reversal of 51123015371 is 17351032115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51123015371 - 222 = 51118821067 is a prime.
It is a super-2 number, since 2×511230153712 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (29).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51123015311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 309506 + ... + 445016.
It is an arithmetic number, because the mean of its divisors is an integer number (6611291700).
Almost surely, 251123015371 is an apocalyptic number.
51123015371 is a deficient number, since it is larger than the sum of its proper divisors (1767318229).
51123015371 is a wasteful number, since it uses less digits than its factorization.
51123015371 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148549.
The product of its (nonzero) digits is 3150, while the sum is 29.
Adding to 51123015371 its reverse (17351032115), we get a palindrome (68474047486).
The spelling of 51123015371 in words is "fifty-one billion, one hundred twenty-three million, fifteen thousand, three hundred seventy-one".
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