Base | Representation |
---|---|
bin | 101111100111001010… |
… | …110100111010110011 |
3 | 11212221211222021001212 |
4 | 233213022310322303 |
5 | 1314144442442342 |
6 | 35252515350335 |
7 | 3456606313655 |
oct | 574712647263 |
9 | 155854867055 |
10 | 51123015347 |
11 | 1a754678108 |
12 | 9aa8bb23ab |
13 | 4a8961b451 |
14 | 268d9406d5 |
15 | 14e3275182 |
hex | be72b4eb3 |
51123015347 has 2 divisors, whose sum is σ = 51123015348. Its totient is φ = 51123015346.
The previous prime is 51123015341. The next prime is 51123015389. The reversal of 51123015347 is 74351032115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51123015347 - 28 = 51123015091 is a prime.
It is a super-2 number, since 2×511230153472 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51123015341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25561507673 + 25561507674.
It is an arithmetic number, because the mean of its divisors is an integer number (25561507674).
Almost surely, 251123015347 is an apocalyptic number.
51123015347 is a deficient number, since it is larger than the sum of its proper divisors (1).
51123015347 is an equidigital number, since it uses as much as digits as its factorization.
51123015347 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 32.
The spelling of 51123015347 in words is "fifty-one billion, one hundred twenty-three million, fifteen thousand, three hundred forty-seven".
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