Base | Representation |
---|---|
bin | 101111100111001011… |
… | …101110100101011111 |
3 | 11212221212102021002011 |
4 | 233213023232211133 |
5 | 1314200023022201 |
6 | 35252524412051 |
7 | 3456611316421 |
oct | 574713564537 |
9 | 155855367064 |
10 | 51123251551 |
11 | 1a754819619 |
12 | 9aa90a7027 |
13 | 4a896a1b08 |
14 | 268d9a2811 |
15 | 14e32c0151 |
hex | be72ee95f |
51123251551 has 8 divisors (see below), whose sum is σ = 52842042000. Its totient is φ = 49432871040.
The previous prime is 51123251521. The next prime is 51123251563. The reversal of 51123251551 is 15515232115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51123251551 - 25 = 51123251519 is a prime.
It is a super-2 number, since 2×511232515512 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51123251521) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7098826 + ... + 7106023.
It is an arithmetic number, because the mean of its divisors is an integer number (6605255250).
Almost surely, 251123251551 is an apocalyptic number.
51123251551 is a deficient number, since it is larger than the sum of its proper divisors (1718790449).
51123251551 is a wasteful number, since it uses less digits than its factorization.
51123251551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14204969.
The product of its digits is 7500, while the sum is 31.
Adding to 51123251551 its reverse (15515232115), we get a palindrome (66638483666).
The spelling of 51123251551 in words is "fifty-one billion, one hundred twenty-three million, two hundred fifty-one thousand, five hundred fifty-one".
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