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5112342404113 = 716371729325799
BaseRepresentation
bin100101001100100111101…
…0110100101110000010001
3200002201211221011120011011
41022121033112211300101
51132230034123412423
614512324440050521
71035232416304120
oct112311726456021
920081757146134
105112342404113
1116a115001053a
126a6981163a41
132b11269621b9
1413961dab5ab7
158ceb52b4b0d
hex4a64f5a5c11

5112342404113 has 16 divisors (see below), whose sum is σ = 5846810860800. Its totient is φ = 4378907941056.

The previous prime is 5112342404047. The next prime is 5112342404149. The reversal of 5112342404113 is 3114042432115.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 5112342404113 - 213 = 5112342395921 is a prime.

It is a super-2 number, since 2×51123424041132 (a number of 26 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (5112342404513) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 198147588 + ... + 198173386.

It is an arithmetic number, because the mean of its divisors is an integer number (365425678800).

Almost surely, 25112342404113 is an apocalyptic number.

It is an amenable number.

5112342404113 is a deficient number, since it is larger than the sum of its proper divisors (734468456687).

5112342404113 is a wasteful number, since it uses less digits than its factorization.

5112342404113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44736.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 5112342404113 its reverse (3114042432115), we get a palindrome (8226384836228).

The spelling of 5112342404113 in words is "five trillion, one hundred twelve billion, three hundred forty-two million, four hundred four thousand, one hundred thirteen".

Divisors: 1 7 1637 11459 17293 25799 121051 180593 28308641 42232963 198160487 295630741 446142107 3122994749 730334629159 5112342404113