Base | Representation |
---|---|
bin | 100101001100100111101… |
… | …0110100101110000010001 |
3 | 200002201211221011120011011 |
4 | 1022121033112211300101 |
5 | 1132230034123412423 |
6 | 14512324440050521 |
7 | 1035232416304120 |
oct | 112311726456021 |
9 | 20081757146134 |
10 | 5112342404113 |
11 | 16a115001053a |
12 | 6a6981163a41 |
13 | 2b11269621b9 |
14 | 13961dab5ab7 |
15 | 8ceb52b4b0d |
hex | 4a64f5a5c11 |
5112342404113 has 16 divisors (see below), whose sum is σ = 5846810860800. Its totient is φ = 4378907941056.
The previous prime is 5112342404047. The next prime is 5112342404149. The reversal of 5112342404113 is 3114042432115.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 5112342404113 - 213 = 5112342395921 is a prime.
It is a super-2 number, since 2×51123424041132 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5112342404513) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 198147588 + ... + 198173386.
It is an arithmetic number, because the mean of its divisors is an integer number (365425678800).
Almost surely, 25112342404113 is an apocalyptic number.
It is an amenable number.
5112342404113 is a deficient number, since it is larger than the sum of its proper divisors (734468456687).
5112342404113 is a wasteful number, since it uses less digits than its factorization.
5112342404113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44736.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 5112342404113 its reverse (3114042432115), we get a palindrome (8226384836228).
The spelling of 5112342404113 in words is "five trillion, one hundred twelve billion, three hundred forty-two million, four hundred four thousand, one hundred thirteen".
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