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5112355013133 = 33154971559281
BaseRepresentation
bin100101001100101000000…
…0110101100001000001101
3200002201212210220011110220
41022121100012230020031
51132230100340410013
614512330010221553
71035232631421114
oct112312006541015
920081783804426
105112355013133
1116a1157142915
126a69854248b9
132b1129458464
14139621638c7b
158ceb6455b23
hex4a6501ac20d

5112355013133 has 8 divisors (see below), whose sum is σ = 7036359588096. Its totient is φ = 3298293556800.

The previous prime is 5112355013093. The next prime is 5112355013153. The reversal of 5112355013133 is 3313105532115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 5112355013133 - 218 = 5112354750989 is a prime.

It is a super-2 number, since 2×51123550131332 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5112355013094 and 5112355013103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112355013153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27485779548 + ... + 27485779733.

It is an arithmetic number, because the mean of its divisors is an integer number (879544948512).

Almost surely, 25112355013133 is an apocalyptic number.

It is an amenable number.

5112355013133 is a deficient number, since it is larger than the sum of its proper divisors (1924004574963).

5112355013133 is a wasteful number, since it uses less digits than its factorization.

5112355013133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 54971559315.

The product of its (nonzero) digits is 20250, while the sum is 33.

The spelling of 5112355013133 in words is "five trillion, one hundred twelve billion, three hundred fifty-five million, thirteen thousand, one hundred thirty-three".

Divisors: 1 3 31 93 54971559281 164914677843 1704118337711 5112355013133