51124343 has 4 divisors (see below), whose sum is σ = 52506120. Its totient is φ = 49742568.

The previous prime is 51124327. The next prime is 51124351. The reversal of 51124343 is 34342115.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34342115 = 5 ⋅6868423.

It is a cyclic number.

It is not a de Polignac number, because 51124343 - 2⁴ = 51124327 is a prime.

It is a super-2 number, since 2×51124343² = 5227396894363298, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51124373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 690833 + ... + 690906.

It is an arithmetic number, because the mean of its divisors is an integer number (13126530).

Almost surely, 2^51124343 is an apocalyptic number.

51124343 is a deficient number, since it is larger than the sum of its proper divisors (1381777).

51124343 is a wasteful number, since it uses less digits than its factorization.

51124343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1381776.

The product of its digits is 1440, while the sum is 23.

The square root of 51124343 is about 7150.1288799573. The cubic root of 51124343 is about 371.1441161684.

Adding to 51124343 its reverse (34342115), we get a palindrome (85466458).

The spelling of 51124343 in words is "fifty-one million, one hundred twenty-four thousand, three hundred forty-three".