5112502431133 has 4 divisors (see below), whose sum is σ = 5112663745600. Its totient is φ = 5112341116668.

The previous prime is 5112502431107. The next prime is 5112502431187. The reversal of 5112502431133 is 3311342052115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5112502431133 - 2¹³ = 5112502422941 is a prime.

It is a super-2 number, since 2×5112502431133² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5112502431095 and 5112502431104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112502431433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80609685 + ... + 80673082.

It is an arithmetic number, because the mean of its divisors is an integer number (1278165936400).

Almost surely, 2^{5112502431133} is an apocalyptic number.

It is an amenable number.

5112502431133 is a deficient number, since it is larger than the sum of its proper divisors (161314467).

5112502431133 is a wasteful number, since it uses less digits than its factorization.

5112502431133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161314466.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 5112502431133 its reverse (3311342052115), we get a palindrome (8423844483248).

The spelling of 5112502431133 in words is "five trillion, one hundred twelve billion, five hundred two million, four hundred thirty-one thousand, one hundred thirty-three".