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5112503 = 11464773
BaseRepresentation
bin10011100000001010110111
3100121202000222
4103200022313
52302100003
6301324555
761312154
oct23401267
910552028
105112503
112982110
12186675b
1310a0066
1497122b
156aec38
hex4e02b7

5112503 has 4 divisors (see below), whose sum is σ = 5577288. Its totient is φ = 4647720.

The previous prime is 5112491. The next prime is 5112511. The reversal of 5112503 is 3052115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5112503 - 24 = 5112487 is a prime.

It is a super-2 number, since 2×51125032 = 52275373850018, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 232376 + ... + 232397.

It is an arithmetic number, because the mean of its divisors is an integer number (1394322).

Almost surely, 25112503 is an apocalyptic number.

5112503 is a deficient number, since it is larger than the sum of its proper divisors (464785).

5112503 is a wasteful number, since it uses less digits than its factorization.

5112503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 464784.

The product of its (nonzero) digits is 150, while the sum is 17.

The square root of 5112503 is about 2261.0844743176. The cubic root of 5112503 is about 172.2706101674.

Adding to 5112503 its reverse (3052115), we get a palindrome (8164618).

The spelling of 5112503 in words is "five million, one hundred twelve thousand, five hundred three".

Divisors: 1 11 464773 5112503