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5112510110031 = 31704170036677
BaseRepresentation
bin100101001100101100101…
…0110010101100101001111
3200002202021121201220102110
41022121121112111211033
51132230410042010111
614512353230355103
71035236523626502
oct112313126254517
920082247656373
105112510110031
1116a1226746475
126a6a0935ba93
132b115262027c
1413963808d139
158cec4d905a6
hex4a65959594f

5112510110031 has 4 divisors (see below), whose sum is σ = 6816680146712. Its totient is φ = 3408340073352.

The previous prime is 5112510110027. The next prime is 5112510110051. The reversal of 5112510110031 is 1300110152115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 5112510110031 - 22 = 5112510110027 is a prime.

It is a super-2 number, since 2×51125101100312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5112510110021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 852085018336 + ... + 852085018341.

It is an arithmetic number, because the mean of its divisors is an integer number (1704170036678).

Almost surely, 25112510110031 is an apocalyptic number.

5112510110031 is a deficient number, since it is larger than the sum of its proper divisors (1704170036681).

5112510110031 is a wasteful number, since it uses less digits than its factorization.

5112510110031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1704170036680.

The product of its (nonzero) digits is 150, while the sum is 21.

Adding to 5112510110031 its reverse (1300110152115), we get a palindrome (6412620262146).

The spelling of 5112510110031 in words is "five trillion, one hundred twelve billion, five hundred ten million, one hundred ten thousand, thirty-one".

Divisors: 1 3 1704170036677 5112510110031