Base | Representation |
---|---|
bin | 1110111000010010001… |
… | …00110000111010110010 |
3 | 1210212122010101020020120 |
4 | 13130021010300322302 |
5 | 31334021324231424 |
6 | 1030511101351110 |
7 | 51636222535161 |
oct | 7341104607262 |
9 | 1725563336216 |
10 | 511253352114 |
11 | 1879042094aa |
12 | 83101868496 |
13 | 392986bc7cb |
14 | 1aa5da033d8 |
15 | d473a69a79 |
hex | 7709130eb2 |
511253352114 has 16 divisors (see below), whose sum is σ = 1047445892640. Its totient is φ = 166261252640.
The previous prime is 511253352109. The next prime is 511253352131. The reversal of 511253352114 is 411253352115.
It is a super-2 number, since 2×5112533521142 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1039132584 + ... + 1039133075.
It is an arithmetic number, because the mean of its divisors is an integer number (65465368290).
Almost surely, 2511253352114 is an apocalyptic number.
511253352114 is an abundant number, since it is smaller than the sum of its proper divisors (536192540526).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
511253352114 is a wasteful number, since it uses less digits than its factorization.
511253352114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2078265705.
The product of its digits is 18000, while the sum is 33.
Subtracting from 511253352114 its reverse (411253352115), we obtain a palindrome (99999999999).
The spelling of 511253352114 in words is "five hundred eleven billion, two hundred fifty-three million, three hundred fifty-two thousand, one hundred fourteen".
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