Base | Representation |
---|---|
bin | 100101001100110001001… |
… | …0010100110110000000001 |
3 | 200002202200002000112122011 |
4 | 1022121202102212300001 |
5 | 1132231211443023341 |
6 | 14512420150012521 |
7 | 1035243325016110 |
oct | 112314222466001 |
9 | 20082602015564 |
10 | 5112660126721 |
11 | 16a12a339a204 |
12 | 6a6a4b647141 |
13 | 2b1177726944 |
14 | 13964dd7dc77 |
15 | 8ced3124b81 |
hex | 4a6624a6c01 |
5112660126721 has 32 divisors (see below), whose sum is σ = 6255922595328. Its totient is φ = 4082877173760.
The previous prime is 5112660126709. The next prime is 5112660126781. The reversal of 5112660126721 is 1276210662115.
It is not a de Polignac number, because 5112660126721 - 233 = 5104070192129 is a prime.
It is a super-3 number, since 3×51126601267213 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (5112660126781) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3445161 + ... + 4700473.
It is an arithmetic number, because the mean of its divisors is an integer number (195497581104).
Almost surely, 25112660126721 is an apocalyptic number.
It is an amenable number.
5112660126721 is a deficient number, since it is larger than the sum of its proper divisors (1143262468607).
5112660126721 is a wasteful number, since it uses less digits than its factorization.
5112660126721 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1256001.
The product of its (nonzero) digits is 60480, while the sum is 40.
Adding to 5112660126721 its reverse (1276210662115), we get a palindrome (6388870788836).
The spelling of 5112660126721 in words is "five trillion, one hundred twelve billion, six hundred sixty million, one hundred twenty-six thousand, seven hundred twenty-one".
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