Base | Representation |
---|---|
bin | 101111100111011010… |
… | …100001111010010010 |
3 | 11212222010201101202212 |
4 | 233213122201322102 |
5 | 1314202021204134 |
6 | 35253143512122 |
7 | 3456656310164 |
oct | 574732417222 |
9 | 155863641685 |
10 | 51127131794 |
11 | 1a756a29932 |
12 | 9aaa458642 |
13 | 4a8a43000b |
14 | 26902d2934 |
15 | 14e37d9bce |
hex | be76a1e92 |
51127131794 has 4 divisors (see below), whose sum is σ = 76690697694. Its totient is φ = 25563565896.
The previous prime is 51127131793. The next prime is 51127131799. The reversal of 51127131794 is 49713172115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 26736501169 + 24390630625 = 163513^2 + 156175^2 .
It is a super-2 number, since 2×511271317942 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51127131793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12781782947 + ... + 12781782950.
Almost surely, 251127131794 is an apocalyptic number.
51127131794 is a deficient number, since it is larger than the sum of its proper divisors (25563565900).
51127131794 is a wasteful number, since it uses less digits than its factorization.
51127131794 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25563565899.
The product of its digits is 52920, while the sum is 41.
The spelling of 51127131794 in words is "fifty-one billion, one hundred twenty-seven million, one hundred thirty-one thousand, seven hundred ninety-four".
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