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51127655043301 = 11323912757148399
BaseRepresentation
bin10111010000000000101011…
…01101111001000011100101
320201000202102012001210101121
423220000111231321003211
523200133414142341201
6300423415342253541
713524564645222064
oct1350002555710345
9221022365053347
1051127655043301
1115322131416471
125898a702872b1
13226b417b0a4a5
14c8a83d9081db
155d9e334379a1
hex2e8015b790e5

51127655043301 has 16 divisors (see below), whose sum is σ = 51800337792000. Its totient is φ = 50458872054528.

The previous prime is 51127655043299. The next prime is 51127655043313. The reversal of 51127655043301 is 10334055672115.

It is a cyclic number.

It is not a de Polignac number, because 51127655043301 - 21 = 51127655043299 is a prime.

It is a super-2 number, since 2×511276550433012 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51127655043391) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 344454100 + ... + 344602498.

It is an arithmetic number, because the mean of its divisors is an integer number (3237521112000).

Almost surely, 251127655043301 is an apocalyptic number.

It is an amenable number.

51127655043301 is a deficient number, since it is larger than the sum of its proper divisors (672682748699).

51127655043301 is a wasteful number, since it uses less digits than its factorization.

51127655043301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161508.

The product of its (nonzero) digits is 378000, while the sum is 43.

The spelling of 51127655043301 in words is "fifty-one trillion, one hundred twenty-seven billion, six hundred fifty-five million, forty-three thousand, three hundred one".

Divisors: 1 113 239 12757 27007 148399 1441541 3048923 16769087 35467361 344528299 1893126043 4007811793 213923242859 452457124277 51127655043301