Base | Representation |
---|---|
bin | 10111010000000000101011… |
… | …01101111001000011100101 |
3 | 20201000202102012001210101121 |
4 | 23220000111231321003211 |
5 | 23200133414142341201 |
6 | 300423415342253541 |
7 | 13524564645222064 |
oct | 1350002555710345 |
9 | 221022365053347 |
10 | 51127655043301 |
11 | 15322131416471 |
12 | 5898a702872b1 |
13 | 226b417b0a4a5 |
14 | c8a83d9081db |
15 | 5d9e334379a1 |
hex | 2e8015b790e5 |
51127655043301 has 16 divisors (see below), whose sum is σ = 51800337792000. Its totient is φ = 50458872054528.
The previous prime is 51127655043299. The next prime is 51127655043313. The reversal of 51127655043301 is 10334055672115.
It is a cyclic number.
It is not a de Polignac number, because 51127655043301 - 21 = 51127655043299 is a prime.
It is a super-2 number, since 2×511276550433012 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51127655043391) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 344454100 + ... + 344602498.
It is an arithmetic number, because the mean of its divisors is an integer number (3237521112000).
Almost surely, 251127655043301 is an apocalyptic number.
It is an amenable number.
51127655043301 is a deficient number, since it is larger than the sum of its proper divisors (672682748699).
51127655043301 is a wasteful number, since it uses less digits than its factorization.
51127655043301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161508.
The product of its (nonzero) digits is 378000, while the sum is 43.
The spelling of 51127655043301 in words is "fifty-one trillion, one hundred twenty-seven billion, six hundred fifty-five million, forty-three thousand, three hundred one".
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