Base | Representation |
---|---|
bin | 10111010000000110011101… |
… | …10001000010100101011111 |
3 | 20201001001102112221100020221 |
4 | 23220003032301002211133 |
5 | 23200211243432404402 |
6 | 300425051405022211 |
7 | 13525034614041325 |
oct | 1350031661024537 |
9 | 221031375840227 |
10 | 51130759653727 |
11 | 15323484937206 |
12 | 5899597b54967 |
13 | 226b7c108ab90 |
14 | c8aa55d81d15 |
15 | 5da065c92337 |
hex | 2e80cec4295f |
51130759653727 has 4 divisors (see below), whose sum is σ = 55063895011720. Its totient is φ = 47197624295736.
The previous prime is 51130759653689. The next prime is 51130759653773. The reversal of 51130759653727 is 72735695703115.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51130759653727 is a prime.
It is a super-2 number, since 2×511307596537272 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51130759653427) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1966567678977 + ... + 1966567679002.
It is an arithmetic number, because the mean of its divisors is an integer number (13765973752930).
Almost surely, 251130759653727 is an apocalyptic number.
51130759653727 is a deficient number, since it is larger than the sum of its proper divisors (3933135357993).
51130759653727 is a wasteful number, since it uses less digits than its factorization.
51130759653727 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3933135357992.
The product of its (nonzero) digits is 41674500, while the sum is 61.
The spelling of 51130759653727 in words is "fifty-one trillion, one hundred thirty billion, seven hundred fifty-nine million, six hundred fifty-three thousand, seven hundred twenty-seven".
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