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51131701 = 59866639
BaseRepresentation
bin1100001100001…
…1010100110101
310120012202111201
43003003110311
5101042203301
65023532501
71160420005
oct303032465
9116182451
1051131701
1126954005
121515a131
13a79355a
146b10005
154750201
hex30c3535

51131701 has 4 divisors (see below), whose sum is σ = 51998400. Its totient is φ = 50265004.

The previous prime is 51131693. The next prime is 51131719. The reversal of 51131701 is 10713115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51131701 - 23 = 51131693 is a prime.

It is a super-2 number, since 2×511317012 = 5228901694306802, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (51131761) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 433261 + ... + 433378.

It is an arithmetic number, because the mean of its divisors is an integer number (12999600).

Almost surely, 251131701 is an apocalyptic number.

It is an amenable number.

51131701 is a deficient number, since it is larger than the sum of its proper divisors (866699).

51131701 is an equidigital number, since it uses as much as digits as its factorization.

51131701 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 866698.

The product of its (nonzero) digits is 105, while the sum is 19.

The square root of 51131701 is about 7150.6433976251. The cubic root of 51131701 is about 371.1619207812.

Adding to 51131701 its reverse (10713115), we get a palindrome (61844816).

The spelling of 51131701 in words is "fifty-one million, one hundred thirty-one thousand, seven hundred one".

Divisors: 1 59 866639 51131701