Base | Representation |
---|---|
bin | 100101001101000001110… |
… | …1010111001110000011011 |
3 | 200002211010002210101010121 |
4 | 1022122003222321300123 |
5 | 1132233333324103110 |
6 | 14512551513054111 |
7 | 1035263235052024 |
oct | 112320352716033 |
9 | 20084102711117 |
10 | 5113220144155 |
11 | 16a1560519632 |
12 | 6a6b870b7337 |
13 | 2b12367638c6 |
14 | 1396a44b9c4b |
15 | 8d017395cda |
hex | 4a683ab9c1b |
5113220144155 has 8 divisors (see below), whose sum is σ = 6136655025600. Its totient is φ = 4090048880256.
The previous prime is 5113220144119. The next prime is 5113220144173. The reversal of 5113220144155 is 5514410223115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5113220144155 - 237 = 4975781190683 is a prime.
It is a super-3 number, since 3×51132201441553 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 5113220144155.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65861710 + ... + 65939299.
It is an arithmetic number, because the mean of its divisors is an integer number (767081878200).
Almost surely, 25113220144155 is an apocalyptic number.
5113220144155 is a deficient number, since it is larger than the sum of its proper divisors (1023434881445).
5113220144155 is a wasteful number, since it uses less digits than its factorization.
5113220144155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131808773.
The product of its (nonzero) digits is 24000, while the sum is 34.
The spelling of 5113220144155 in words is "five trillion, one hundred thirteen billion, two hundred twenty million, one hundred forty-four thousand, one hundred fifty-five".
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