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5113243603 = 13393326431
BaseRepresentation
bin1001100001100010…
…11110011111010011
3111012100110200120201
410300301132133103
540432442243403
62203214320031
7240465565516
oct46061363723
914170420521
105113243603
112194324666
12ba84b9017
1363645b440
1436713cd7d
151edd7521d
hex130c5e7d3

5113243603 has 4 divisors (see below), whose sum is σ = 5506570048. Its totient is φ = 4719917160.

The previous prime is 5113243591. The next prime is 5113243607. The reversal of 5113243603 is 3063423115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5113243603 - 221 = 5111146451 is a prime.

It is a super-2 number, since 2×51132436032 = 52290520287240843218, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5113243607) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196663203 + ... + 196663228.

It is an arithmetic number, because the mean of its divisors is an integer number (1376642512).

Almost surely, 25113243603 is an apocalyptic number.

5113243603 is a deficient number, since it is larger than the sum of its proper divisors (393326445).

5113243603 is a wasteful number, since it uses less digits than its factorization.

5113243603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 393326444.

The product of its (nonzero) digits is 6480, while the sum is 28.

The square root of 5113243603 is about 71506.9479351482. The cubic root of 5113243603 is about 1722.7892820457.

Adding to 5113243603 its reverse (3063423115), we get a palindrome (8176666718).

The spelling of 5113243603 in words is "five billion, one hundred thirteen million, two hundred forty-three thousand, six hundred three".

Divisors: 1 13 393326431 5113243603